The difference of the square of a number and 36 is equal to 5 times that number. Find the positive solution.

Step 1 ：The problem is asking for a number that satisfies the equation \(x^2 - 36 = 5x\). This is a quadratic equation, and we can solve it by setting it equal to zero and then factoring or using the quadratic formula.

Step 2 ：The quadratic formula is \(x = [-b ± \sqrt{b^2 - 4ac}] / (2a)\), where a, b, and c are the coefficients of the quadratic equation in the form \(ax^2 + bx + c = 0\). In this case, a = 1, b = -5, and c = -36.

Step 3 ：We are looking for the positive solution, so we will use the plus sign in the quadratic formula.

Step 4 ：Substituting the values of a, b, and c into the quadratic formula, we get two solutions: \(x1 = 9.0\) and \(x2 = -4.0\).

Step 5 ：Since we are looking for the positive solution, we discard \(x2 = -4.0\) and take \(x1 = 9.0\) as the solution.

Step 6 ：Final Answer: The positive solution to the equation is \(\boxed{9}\).