Find the sum. \[ \sum_{k=7}^{10}\left(6-k^{2}\right) \] $\sum_{k=7}^{10}\left(6-k^{2}\right)=\square($ Simplify your answer.)

Step 1 ：We are given the sum \(\sum_{k=7}^{10}\left(6-k^{2}\right)\) and we are asked to find its value.

Step 2 ：We can calculate this sum by iterating over the range of values from 7 to 10 (inclusive), calculating the value of the function \(6 - k^2\) for each \(k\), and adding them up.

Step 3 ：Let's calculate the sum: \(-1 + (-20) + (-45) + (-76) = -142\)

Step 4 ：So, the sum \(\sum_{k=7}^{10}\left(6-k^{2}\right) = -142\)

Step 5 ：Final Answer: \(\boxed{-142}\)