Step 1 :First, find the minimum of each row in the matrix.
Step 2 :For the first row, the minimum is \(4\).
Step 3 :For the second row, the minimum is \(-3\).
Step 4 :For the third row, the minimum is \(4\).
Step 5 :Next, find the maximum of each column in the matrix.
Step 6 :For the first column, the maximum is \(4\).
Step 7 :For the second column, the maximum is \(4\).
Step 8 :For the third column, the maximum is \(9\).
Step 9 :The intersection of the row minimum and column maximum gives us the saddle points. In this case, we have two saddle points: \((1,1)\) and \((1,2)\) where the value is \(4\), and \((3,3)\) where the value is \(9\).
Step 10 :For the second part, again find the minimum of each row in the matrix.
Step 11 :For the first row, the minimum is \(6\).
Step 12 :For the second row, the minimum is \(1\).
Step 13 :For the third row, the minimum is \(6\).
Step 14 :Then, find the maximum of each column in the matrix.
Step 15 :For the first column, the maximum is \(6\).
Step 16 :For the second column, the maximum is \(9\).
Step 17 :For the third column, the maximum is \(6\).
Step 18 :For the fourth column, the maximum is \(16\).
Step 19 :The intersection of the row minimum and column maximum gives us the saddle points. In this case, we have one saddle point: \((1,1)\) where the value is \(6\).
Step 20 :So, the final answer is \(\boxed{\text{Saddle points are (1,1), (1,2) with value 4, (3,3) with value 9 for the first matrix and (1,1) with value 6 for the second matrix.}}\)