Question 4 Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of $0^{\circ} \mathrm{C}$ and a standard deviation of $1.00^{\circ} \mathrm{C}$. A single thermometer is randomly selected and tested. Find $P_{69}$, the 69 -percentile. This is the temperature reading separating the bottom $69 \%$ from the top $31 \%$. \[ P_{69}= \] ${ }^{\circ} \mathrm{C}$ (Round answer to three decimal places) Question Help: Video Submit Question

Step 1 ：The problem is asking for the 69th percentile of a normal distribution with a mean of 0 and a standard deviation of 1. The percentile of a distribution is the value below which a certain percent of the observations fall. So, the 69th percentile is the value below which 69% of the observations fall.

Step 2 ：Using the percentile function with the percentile to calculate as 69 and the standard deviation of the distribution as 1, we get the 69th percentile as approximately 0.496.

Step 3 ：This means that 69% of the temperature readings are below this value.

Step 4 ：Final Answer: The 69th percentile of the temperature readings is approximately \(\boxed{0.496}\) degrees Celsius.