Step 1 :\(\left(\frac{f}{g}\right)(x) = \frac{f(x)}{g(x)} = \frac{\frac{x}{x-9}}{\frac{x+3}{x-9}}\)
Step 2 :Multiply the numerator and the denominator by (x-9) to get rid of the denominator in both fractions: \(\left(\frac{f}{g}\right)(x) = \frac{x}{x+3}\)
Step 3 :Set the denominator equal to zero and solve for x to find the domain: x + 3 = 0, x = -3
Step 4 :The domain of the function is all real numbers except -3. In interval notation, this is: \(\boxed{(-\infty, -3) \cup (-3, \infty)}\)