Problem

3. The sum of two numbers is 86 and the difference is 12 . What are the two numbers? You must use an Algebraic approach to solve this problem.

Solution

Step 1 :Let's denote the two numbers as \(x\) and \(y\).

Step 2 :We are given two equations based on the problem: \(x + y = 86\) and \(x - y = 12\).

Step 3 :We can solve this system of equations using the method of elimination. By adding the two equations together, we can eliminate \(y\) and solve for \(x\).

Step 4 :Once we have the value of \(x\), we can substitute it into one of the original equations to solve for \(y\).

Step 5 :The solution to the system of equations is \(x = 49\) and \(y = 37\).

Step 6 :This means that the two numbers that sum to 86 and have a difference of 12 are 49 and 37.

Step 7 :Final Answer: The two numbers are \(\boxed{49}\) and \(\boxed{37}\).

From Solvely APP
Source: https://solvelyapp.com/problems/ocsKJRdN6G/

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