Step 1 :\(f(g(x))=f(2x-5)=\frac{(2x-5)+5}{2}=\frac{2x}{2}=x\)
Step 2 :\(g(f(x))=g(\frac{x+5}{2})=2(\frac{x+5}{2})-5=x+5-5=x\)
Step 3 :\(\boxed{\text{Since } f(g(x))=x \text{ and } g(f(x))=x, \text{ f and g are inverses of each other.}}\)
Step 4 :\(f(g(x))=f(2x)=2(2x)=4x\)
Step 5 :\(g(f(x))=g(2x)=2(2x)=4x\)
Step 6 :\(\boxed{\text{Since } f(g(x))=4x \text{ and } g(f(x))=4x, \text{ f and g are not inverses of each other.}}\)