If \( A=\begin{pmatrix} 3 & 5 \\ -1 & 2 \end{pmatrix} \) and \( B=\begin{pmatrix} 2 & -1 \\ 3 & 4 \end{pmatrix} \), find the matrix \( C \) such that \( C = 2A - 3B \).

Step 1 ：\( C = 2A - 3B \rightarrow C = 2\begin{pmatrix} 3 & 5 \\ -1 & 2 \end{pmatrix} - 3\begin{pmatrix} 2 & -1 \\ 3 & 4 \end{pmatrix} \)

Step 2 ：\( C = \begin{pmatrix} 6 & 10 \\ -2 & 4 \end{pmatrix} - \begin{pmatrix} 6 & -3 \\ 9 & 12 \end{pmatrix} \)

Step 3 ：\( C = \begin{pmatrix} 6-6 & 10+3 \\ -2-9 & 4-12 \end{pmatrix} \)