Evaluate the integral: \(\int (3x^2-2x+1)e^{x^3-x^2+x} dx\)

Step 1 ：First, let's make a substitution. We set \(u = x^3 - x^2 + x\), then the differential of \(u\) is \(du = (3x^2 - 2x + 1)dx\)

Step 2 ：Substitute \(u\) and \(du\) into the integral, we get \(\int e^u du\)

Step 3 ：The integral of \(e^u\) with respect to \(u\) is \(e^u\)

Step 4 ：Substitute \(u\) back into the integral, we get \(e^{x^3-x^2+x}\)