Find the ordered pair solution for the following linear equation: \(2x+3y=6\)

Step 1 ：Step 1: We start by setting \(y = 0\) and solve for \(x\): \(2x + 3*0 = 6 \rightarrow 2x = 6 \rightarrow x = 3\), so the first ordered pair is (3,0).

Step 2 ：Step 2: Now we set \(x = 0\) and solve for \(y\): \(2*0 + 3y = 6 \rightarrow 3y = 6 \rightarrow y = 2\), so the second ordered pair is (0,2).