Problem

Question 1 From a group of 9 people, you randomly select 4 of them. What is the probability that they are the 4 oldest people in the group? Give your answer as a fraction Question Help: Dvideb Calculator Submit Question

Solution

Step 1 :The problem is asking for the probability of a specific event happening. In this case, the event is selecting the 4 oldest people from a group of 9.

Step 2 :The total number of ways to select 4 people from a group of 9 is given by the combination formula \(C(n, k) = \frac{n!}{k!(n-k)!}\), where n is the total number of items, k is the number of items to choose, and ! denotes factorial.

Step 3 :The event we are interested in (selecting the 4 oldest people) can happen in only one way.

Step 4 :So, the probability of this event is the number of ways the event can happen divided by the total number of possible events.

Step 5 :Total number of ways to select 4 people from a group of 9 is 126.

Step 6 :Number of ways the event can happen is 1.

Step 7 :Probability = \(\frac{1}{126}\)

Step 8 :Final Answer: The probability that the 4 oldest people are selected from the group is \(\boxed{\frac{1}{126}}\).

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Source: https://solvelyapp.com/problems/mJj6Am7igr/

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