Find the value of the test statistic $z$ using $z=\frac{\hat{p}-p}{\sqrt{\frac{p q}{n}}}$. A claim is made that the proportion of children who play sports is less than 0.5 , and the sample statistics include $n=1320$ subjects with $30 \%$ saying that they play a sport. 14.53 $-14.53$ 29.66 $-29.66$

Step 1 ：Substitute the given values into the formula: \(z = \frac{\hat{p} - p}{\sqrt{\frac{p q}{n}}}\)

Step 2 ：Substitute \(n = 1320\), \(\hat{p} = 0.30\), and \(p = 0.5\) into the formula

Step 3 ：Simplify the denominator: \(\sqrt{\frac{0.5 \cdot (1-0.5)}{1320}} = \sqrt{\frac{0.25}{1320}}\)

Step 4 ：Calculate the square root of 5280: \(\sqrt{5280} = 72.7279\)

Step 5 ：Multiply \(-0.20\) by \(72.7279\): \(-0.20 \cdot 72.7279 = -14.5456\)

Step 6 ：Round to two decimal places: \(-14.5456 \approx -14.55\)

Step 7 ：The correct answer is \(\boxed{-14.55}\)