Problem

Factor $f(x)$ into linear factors given that $k$ is a zero of $f(x)$. 8) $f(x)=x^{3}-2 x^{2}-36 x+72 ; k=6$

Solution

Step 1 :Given that $k=6$ is a zero of $f(x)$, we can say that $(x-6)$ is a factor of $f(x)$ according to the Factor Theorem.

Step 2 :Next, we perform polynomial division of $f(x)$ by $(x-6)$ to find the other factors of $f(x)$.

Step 3 :Finally, we factorize the quotient obtained from the polynomial division to get the linear factors of $f(x)$.

Step 4 :The linear factors of $f(x)$ are \(\boxed{(x-6)}, \boxed{(x-2)}, \boxed{(x+6)}\).

From Solvely APP
Source: https://solvelyapp.com/problems/l4BaO8mvM3/

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