Problem

$f(x)=3 x^{3}-5 x^{2}-3 x+2 ; f(-4)$ $f(-4)=\square$

Solution

Step 1 :The function given is \(f(x)=3 x^{3}-5 x^{2}-3 x+2\). We are asked to find the value of \(f(-4)\).

Step 2 :To find this, we substitute \(x=-4\) into the function.

Step 3 :So, \(f(-4)=3(-4)^{3}-5(-4)^{2}-3(-4)+2\).

Step 4 :Simplifying this expression, we find that \(f(-4)=-258\).

Step 5 :Therefore, the final answer is \(\boxed{-258}\).

From Solvely APP
Source: https://solvelyapp.com/problems/l3vfToXKP1/

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