Consider the following frequency table representing the distribution of hours students study for an exam in a week. \begin{tabular}{|c|c|} \hline \multicolumn{2}{|c|}{\begin{tabular}{c} Hours \\ Students study for \\ an exam in a week \end{tabular}} \\ \hline Class & Frequency \\ \hline $18-28$ & 11 \\ \hline $29-39$ & 5 \\ \hline $40-50$ & 8 \\ \hline $51-61$ & 2 \\ \hline $62-72$ & 15 \\ \hline \end{tabular} Copy Data Determine the class width of each class.

Step 1 ：Consider the following frequency table representing the distribution of hours students study for an exam in a week. The classes are 18-28, 29-39, 40-50, 51-61, and 62-72.

Step 2 ：The class width can be determined by subtracting the lower limit of a class from the upper limit.

Step 3 ：For each class, subtract the lower limit from the upper limit to find the class width.

Step 4 ：The class widths are calculated as follows: \(28 - 18 = 10\), \(39 - 29 = 10\), \(50 - 40 = 10\), \(61 - 51 = 10\), \(72 - 62 = 10\).

Step 5 ：Final Answer: The class width of each class is \(\boxed{10}\).