To rent a certain meeting room, a college charges a reservation fee of $\$ 44$ and an additional fee of $\$ 5.60$ per hour. The math club wants to spend at most $\$ 66.40$ on renting the meeting room. What are the possible amounts of time for which they could rent the meeting room? Use $t$ for the number of hours the meeting room is rented, and solve your inequality for $t$. (1) $\square<\square \quad \square>\square \quad \square \leq \square$ $\square \geq \square$ \[ \times \quad 3 \]

Step 1 ：The problem is asking for the possible amounts of time the math club can rent the meeting room without exceeding a total cost of $66.40. The total cost is composed of a fixed reservation fee of $44 and an additional fee of $5.60 per hour. We can represent this as an inequality where the total cost (44 + 5.60t) is less than or equal to $66.40. We need to solve this inequality for t.

Step 2 ：Set up the inequality: \(44 + 5.60t \leq 66.40\)

Step 3 ：Solve the inequality for t: \(t \leq 4\)

Step 4 ：The solution to the equation is 4. This means that the math club can rent the meeting room for exactly 4 hours without exceeding the total cost of $66.40. However, the problem asks for the possible amounts of time, which means we need to consider the time less than or equal to 4 hours.

Step 5 ：Final Answer: The possible amounts of time for which they could rent the meeting room are \(t \leq 4\) hours. So, the final answer is \(\boxed{t \leq 4}\).