Step 1 :The problem provides the marital status distribution of the male population age 18 or older as follows: Never Married (32.9%), Married (52.7%), Widowed (2.9%), Divorced (11.5%).
Step 2 :We are given a random sample of 1812 adult men from California and we are asked to test the claim that the distribution from California is as expected at the \( \alpha=0.05 \) significance level.
Step 3 :To do this, we first need to calculate the expected frequencies for each marital status category. The expected frequency is calculated by multiplying the total sample size by the proportion of each category in the population.
Step 4 :The proportions for each category are given as percentages in the problem. We need to convert these percentages to proportions by dividing by 100. So, the proportions are: Never Married: 0.329, Married: 0.527, Widowed: 0.029, Divorced: 0.115.
Step 5 :Then we can calculate the expected frequency for each category by multiplying the total sample size (1812) by the proportion of each category. The expected frequencies are: Never Married: \(1812 \times 0.329 = 596\), Married: \(1812 \times 0.527 = 955\), Widowed: \(1812 \times 0.029 = 53\), Divorced: \(1812 \times 0.115 = 208\).
Step 6 :Final Answer: The expected frequencies for each category are as follows: \n\begin{tabular}{|c|l|l|}\n\hline Outcome & Frequency & Expected Frequency \\n\hline Never Married & 616 & \(\boxed{596}\) \\n\hline Married & 934 & \(\boxed{955}\) \\n\hline Widowed & 44 & \(\boxed{53}\) \\n\hline Divorced & 218 & \(\boxed{208}\) \\n\hline\n\end{tabular}