Problem

Trials in an experiment with a polygraph include 99 results that include 22 cases of wrong results and 77 cases of correct results. Use a 0.01 significance level to test the claim that such polygraph results are correct less than $80 \%$ of the time. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method. Use the normal distribution as an approximation of the binomial distribution. Let $\mathrm{p}$ be the population proportion of correct polygraph results. Identify the null and alternative hypotheses. Choose the correct answer below. A. \[ \begin{array}{l} H_{0}: p=0.20 \\ H_{1}: p<0.20 \end{array} \] C. \[ \begin{array}{l} H_{0}: p=0.80 \\ H_{1}: p>0.80 \end{array} \] E. \[ \begin{array}{l} H_{0}: p=0.80 \\ H_{1}: p<0.80 \end{array} \] B. \[ \begin{array}{l} H_{0}: p=0.80 \\ H_{1}: p \neq 0.80 \end{array} \] D. \[ \begin{array}{l} H_{0}: p=0.20 \\ H_{1}: p \neq 0.20 \end{array} \] F. \[ \begin{array}{l} H_{0}: p=0.20 \\ H_{1}: p>0.20 \end{array} \] The test statistic is $z=\square$. (Round to two decimal places as needed.) The P-value is $\square$. (Round to four decimal places as needed.) Identify the conclusion about the null hypothesis and the final conclusion that addresses the original claim. $\mathrm{H}_{0}$. There sufficient evidence to support the claim that the polygraph results are correct less than $80 \%$ of the time. (1) Time Remaining: 00:01:49 Next

Solution

Step 1 :Given values are: total number of trials \(n = 99\), number of correct results \(x = 77\), null hypothesis population proportion \(p0 = 0.80\), and significance level \(\alpha = 0.01\).

Step 2 :Calculate the sample proportion \(p_{hat} = \frac{x}{n} = \frac{77}{99} = 0.7777777777777778\).

Step 3 :Calculate the standard error \(se = \sqrt{\frac{p0 * (1 - p0)}{n}} = \sqrt{\frac{0.8 * (1 - 0.8)}{99}} = 0.04020151261036848\).

Step 4 :Calculate the test statistic \(z = \frac{p_{hat} - p0}{se} = \frac{0.7777777777777778 - 0.8}{0.04020151261036848} = -0.5527707983925675\).

Step 5 :Calculate the P-value using the cumulative distribution function of the normal distribution. The P-value is approximately 0.29.

Step 6 :Since the P-value is greater than the significance level of 0.01, we fail to reject the null hypothesis.

Step 7 :This means that there is not enough evidence to support the claim that the polygraph results are correct less than 80% of the time.

Step 8 :The null and alternative hypotheses are: \(H_{0}: p=0.80\) and \(H_{1}: p<0.80\).

Step 9 :The test statistic is \(z=-0.55\).

Step 10 :The P-value is \(0.29\).

Step 11 :There is not enough evidence to reject the null hypothesis. Therefore, there is not enough evidence to support the claim that the polygraph results are correct less than 80% of the time.

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