(1 point) (Section 4.3) A car comes to a stop six seconds after the driver applies the brakes. While the brakes are on, the following velocities are recorded: \begin{tabular}{|c|c|c|c|c|} \hline Time since brakes applied (sec) & 0 & 2 & 4 & 6 \\ \hline Velocity (ft/s) & 91 & 46 & 17 & 0 \\ \hline \end{tabular} Give lower and upper estimates (using all of the available data) for the distance the car traveled after the brakes were applied. lower: upper: (for each, include units) On a sketch of velocity against time, show the lower and upper estimates you found above..

Step 1 ：Given the time intervals and the corresponding velocities, we can calculate the lower and upper estimates for the distance the car traveled after the brakes were applied.

Step 2 ：The time intervals are \(0, 2, 4, 6\) seconds and the corresponding velocities are \(91, 46, 17, 0\) feet per second.

Step 3 ：We calculate the differences in time, which are \(2, 2, 2\) seconds.

Step 4 ：For the lower estimates, we take the minimum velocity for each time interval, which gives us \(92, 34, 0\) feet.

Step 5 ：For the upper estimates, we take the maximum velocity for each time interval, which gives us \(182, 92, 34\) feet.

Step 6 ：We sum up the lower estimates to get a total lower estimate of \(126\) feet.

Step 7 ：We sum up the upper estimates to get a total upper estimate of \(308\) feet.

Step 8 ：Thus, the lower estimate for the distance the car traveled after the brakes were applied is \(\boxed{126}\) feet and the upper estimate is \(\boxed{308}\) feet.