IQ scores have a population mean of 100 , a population standard deviation of 15 , and are approximately Normally distributed. Use one of the StatCrunch outputs below to find the probability that a randomly selected person will have an IQ of 70 or above. State whether Figure (A) or Figure (B) is the correct representation of a person with an IQ of 70 or above. Figure (A) Figure (B) Use to find the probability. The probability that a randomly selected person will have an IQ of 70 or above is $\square$. (Round to four decimal places as needed.)

Step 1 ：The question is asking for the probability that a randomly selected person will have an IQ of 70 or above. Given that IQ scores are normally distributed with a mean of 100 and a standard deviation of 15, we can use the standard normal distribution to find this probability.

Step 2 ：First, we need to convert the IQ score of 70 to a z-score, which is a measure of how many standard deviations an element is from the mean. The formula for calculating the z-score is: \(z = \frac{X - \mu}{\sigma}\) where: \(X\) is the value we are interested in (in this case, 70), \(\mu\) is the mean (in this case, 100), and \(\sigma\) is the standard deviation (in this case, 15).

Step 3 ：After calculating the z-score, we can use the standard normal distribution table to find the probability that a randomly selected person will have an IQ of 70 or above.

Step 4 ：Using the given values, the z-score is calculated as \(z = \frac{70 - 100}{15} = -2.0\).

Step 5 ：Using the standard normal distribution table, the probability corresponding to a z-score of -2.0 is approximately 0.9772.

Step 6 ：Final Answer: The probability that a randomly selected person will have an IQ of 70 or above is \(\boxed{0.9772}\). This means that about 97.72% of the population will have an IQ of 70 or above. This makes sense, as an IQ of 70 is quite low, and most people would be expected to have an IQ higher than this.