These data are the number of on-campus burglanes reported in a given year for nine western Pennsyivanla universities. $\begin{array}{llllllllll}\text { is } & 11 & 2 & 15 & 9 & 8 & 13 & 6 & 15\end{array}$ For the above data set, find the mean, median, midrange, and mode, Round to one decimal place, if necessary. Part: $0 / 4$ Part 1 of 4 (a) Find the mean. The mean is $\square$ burglaries. Next brart

Step 1 ：Given data is the number of on-campus burglaries reported in a given year for nine western Pennsylvania universities: 11, 2, 15, 9, 8, 13, 6, 15.

Step 2 ：To find the mean, we sum up all the numbers and then divide by the count of numbers.

Step 3 ：Adding all the reported burglaries together gives us \(11 + 2 + 15 + 9 + 8 + 13 + 6 + 15 = 79\).

Step 4 ：We then divide this sum by the total number of universities, which is 9. So, the mean is \( \frac{79}{9} = 8.777777777777779 \).

Step 5 ：Rounding to one decimal place, the mean is 8.8.

Step 6 ：Final Answer: The mean is \( \boxed{8.8} \) burglaries.