Step 1 :Write the division problem in long division format: \(x - 3\) into \(x^3 + 4x^2 + 2x\)
Step 2 :Divide the first term in the dividend (\(x^3\)) by the first term in the divisor (\(x\)), to get \(x^2\)
Step 3 :Multiply the divisor (\(x - 3\)) by the result from step 2 (\(x^2\)), to get \(x^3 - 3x^2\)
Step 4 :Subtract the result from step 3 (\(x^3 - 3x^2\)) from the first two terms of the dividend (\(x^3 + 4x^2\)), to get \(7x^2\)
Step 5 :Bring down the next term from the dividend (\(2x\)), to get \(7x^2 + 2x\)
Step 6 :Repeat steps 2-5 with the new dividend (\(7x^2 + 2x\)), to get \(7x\) and \(21x^2 - 6x\)
Step 7 :Subtract \(21x^2 - 6x\) from \(7x^2 + 2x\), to get \(-14x^2 + 8x\)
Step 8 :The divisor (\(x - 3\)) does not divide evenly into the new dividend (\(-14x^2 + 8x\)), so the remainder is \(-14x^2 + 8x\)
Step 9 :The final result of the division is the quotient (\(x^2 + 7x\)) plus the remainder (\(-14x^2 + 8x\)) divided by the divisor (\(x - 3\))
Step 10 :So, \(x^3 + 4x^2 + 2x\) divided by \(x - 3\) is \(x^2 + 7x - \frac{{14x^2 + 8x}}{{x - 3}}\)