Question Watch Video Show Examples What is the equation of the line that passes through the point $(-5,-6)$ and has a slope of $\frac{1}{5}$ ? Answer Attempt 1 out of 2 Submit Answer opyright 02023 DeltaMath.com All Rights Reserved: Privacy Policy / Terms of Service

Step 1 ：We are given the equation of a line in slope-intercept form: \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

Step 2 ：We are given the slope \(m = \frac{1}{5}\) and a point on the line \((-5,-6)\).

Step 3 ：We substitute these values into the equation to solve for \(b\): \(-6 = \frac{1}{5}*(-5) + b\).

Step 4 ：Solving for \(b\), we get \(b = -5\).

Step 5 ：Substituting \(m\) and \(b\) back into the equation, we get the final equation of the line: \(y = \frac{1}{5}x - 5\).

Step 6 ：\(\boxed{y = \frac{1}{5}x - 5}\) is the equation of the line that passes through the point \((-5,-6)\) and has a slope of \(\frac{1}{5}\).