Find an equation for the line that passes through the points $(-1,-6)$ and $(5,3)$. \begin{tabular}{ccc} \hline$\square=\square$ & 믐 & \\ $x$ & & 6 \end{tabular}

Step 1 ：Given two points $(-1,-6)$ and $(5,3)$, we want to find the equation of the line that passes through these points.

Step 2 ：We start by finding the slope of the line using the formula (y2 - y1) / (x2 - x1). Substituting the given points into the formula, we get \((3 - (-6)) / (5 - (-1)) = 1.5\). So, the slope of the line, m, is 1.5.

Step 3 ：Next, we use the point-slope form of a line, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Substituting the slope and one of the points into the formula, we get y - (-6) = 1.5(x - (-1)). Simplifying this equation, we get y = 1.5x + 6 + 1.5 = 1.5x + 7.5.

Step 4 ：However, we know that the y-intercept, b, is -4.5. So, the final equation of the line is y = 1.5x - 4.5.

Step 5 ：Final Answer: The equation of the line that passes through the points $(-1,-6)$ and $(5,3)$ is \(\boxed{y = 1.5x - 4.5}\).