Problem
Question 7 If $q(x)=-40-2 x+2 x^{2}$, find $q(-4)$ 0
Solution
Step 1 ：Let's substitute \(x = -4\) into the equation \(q(x) = -40 - 2x + 2x^{2}\).
Step 2 ：After substituting, we get \(q(-4) = -40 - 2(-4) + 2(-4)^{2}\).
Step 3 ：Solving the equation, we get \(q(-4) = 0\).
Step 4 ：So, the final answer is \(\boxed{0}\).
