Area involving rectangles and circles A rose garden is formed by joining a rectangle and a semicircle, as shown below. The rectangle is $28 \mathrm{ft}$ long and $20 \mathrm{ft}$ wide. Find the area of the garden. Do not round any intermediate steps. Round your final answer to the nearest hundredth and be sure to include the correct unit. If necessary, refer to the list of geometry formulas.

Step 1 ：The rose garden is formed by joining a rectangle and a semicircle. The rectangle is \(28 \, \text{ft}\) long and \(20 \, \text{ft}\) wide.

Step 2 ：The area of the garden can be calculated by adding the area of the rectangle and the area of the semicircle.

Step 3 ：The area of a rectangle is given by the formula length * width, so the area of the rectangle is \(28 \, \text{ft} * 20 \, \text{ft} = 560 \, \text{ft}^2\).

Step 4 ：The area of a semicircle is given by the formula \(1/2 * \pi * r^2\), where r is the radius of the semicircle. In this case, the radius of the semicircle is the same as the width of the rectangle, which is \(10 \, \text{ft}\).

Step 5 ：So, the area of the semicircle is \(1/2 * \pi * (10 \, \text{ft})^2 = 157.08 \, \text{ft}^2\).

Step 6 ：Finally, add the area of the rectangle and the area of the semicircle to get the total area of the garden. So, the total area of the garden is \(560 \, \text{ft}^2 + 157.08 \, \text{ft}^2 = 717.08 \, \text{ft}^2\).

Step 7 ：\(\boxed{717.08}\) square feet is the total area of the garden.