Step 1 :Given that the sample mean pulse rate for adult females is 70 bpm, the sample standard deviation is 10 bpm, and the sample size is 100.
Step 2 :We are asked to construct a 95% confidence interval for the mean pulse rate. The formula for the confidence interval for a population mean is \(\bar{x} \pm Z_{\frac{\alpha}{2}} \frac{s}{\sqrt{n}}\), where \(\bar{x}\) is the sample mean, \(Z_{\frac{\alpha}{2}}\) is the Z-score corresponding to the desired confidence level (for a 95% confidence level, \(Z_{\frac{\alpha}{2}} = 1.96\)), \(s\) is the sample standard deviation, and \(n\) is the sample size.
Step 3 :Substituting the given values into the formula, we get \(70 \pm 1.96 \frac{10}{\sqrt{100}}\).
Step 4 :Solving the above expression, we get the lower limit as 68.0 bpm and the upper limit as 72.0 bpm.
Step 5 :Thus, the 95% confidence interval of the mean pulse rate for adult females is \(\boxed{68.0 \, \text{bpm} < \mu < 72.0 \, \text{bpm}}\).