Factor completely. \[ 80 x^{4}-5 y^{4} \]

Step 1 ：Given the expression \(80 x^{4}-5 y^{4}\)

Step 2 ：Recognize that this is a difference of two squares, which can be factored using the formula \(a^2 - b^2 = (a+b)(a-b)\)

Step 3 ：In this case, \(a\) is \(\sqrt{80x^4}\) and \(b\) is \(\sqrt{5y^4}\)

Step 4 ：Factorize the given expression using the difference of squares formula

Step 5 ：The factored form of the expression is \(5*(2*x - y)*(2*x + y)*(4*x^2 + y^2)\)

Step 6 ：Final Answer: The factored form of the expression \(80 x^{4}-5 y^{4}\) is \(\boxed{5*(2*x - y)*(2*x + y)*(4*x^2 + y^2)}\)