Find the reciprocal of $\frac{2 y-1}{x+3}$ (A) $\frac{y-1}{2 x+3}$ (B) $\frac{2 y+3}{x-1}$ (C) $\frac{2 x+3}{y-1}$ (D) $\frac{x+3}{2 y-1}$

Step 1 ：Find the reciprocal of the fraction $\frac{2 y-1}{x+3}$

Step 2 ：The reciprocal of a fraction is obtained by swapping the numerator and the denominator

Step 3 ：So, the reciprocal of $\frac{2 y-1}{x+3}$ is $\frac{x+3}{2 y-1}$

Step 4 ：Therefore, the answer is (D) $\frac{x+3}{2 y-1}$

Step 5 ：Final Answer: \(\boxed{(D) \frac{x+3}{2 y-1}}\)