The function $h$ is defined as $h(x)=\frac{6}{5 x^{2}-3}$. Find $h(x-1)$ Write your answer without parentheses, and simplify it as much as possible. \[ h(x-1)=\frac{6}{5 x^{2}+22} \]

Step 1 ：The function $h$ is defined as $h(x)=\frac{6}{5 x^{2}-3}$.

Step 2 ：We are asked to find $h(x-1)$, which means we need to substitute $x-1$ into the function $h(x)$.

Step 3 ：Substituting $x-1$ into the function gives $h(x-1)=\frac{6}{5 (x-1)^{2}-3}$.

Step 4 ：Thus, the simplified expression for $h(x-1)$ is $h(x-1)=\frac{6}{5(x-1)^{2}-3}$.

Step 5 ：\(\boxed{h(x-1)=\frac{6}{5(x-1)^{2}-3}}\)