Question 16 The table below describes residents of a Chicago neighborhood based on their car ownership and public transportation usage. \begin{tabular}{|l|cc|c|} \hline & Owns car & Does not own car & Total \\ \hline Uses public transport & 34 & 94 & 128 \\ Does not use public transport & 126 & 17 & 143 \\ \hline Total & 160 & 111 & 271 \\ \hline \end{tabular} What is the probability that a randomly selected resident of this neighborhood both owns a car and uses public transport? 0.213 0.125 0.266 0.153

Step 1 ：The question is asking for the probability that a randomly selected resident of this neighborhood both owns a car and uses public transport.

Step 2 ：From the table, we can see that the total number of residents is 271 and the number of residents who both own a car and use public transport is 34.

Step 3 ：So, the probability can be calculated by dividing the number of residents who both own a car and use public transport by the total number of residents.

Step 4 ：\(\text{total residents} = 271\)

Step 5 ：\(\text{residents own car and use public transport} = 34\)

Step 6 ：\(\text{probability} = \frac{\text{residents own car and use public transport}}{\text{total residents}} = \frac{34}{271} = 0.12546125461254612\)

Step 7 ：The probability that a randomly selected resident of this neighborhood both owns a car and uses public transport is approximately \(\boxed{0.125}\).