Problem

A projectile is fired vertically upward and can be modeled by the function $h(t)=-16 t^{2}+800 t+175$. During what time interval will the projectile be more than 1000 feet above the ground? Round your answer to the nearest hundredth. Atranscript Answer How to enter your answer (opens in new window) Keypad Keyboard Shortcuts \[

Solution

Step 1 :The question is asking for the time interval during which the height of the projectile is more than 1000 feet. This means we need to solve the inequality \(h(t) > 1000\) for \(t\).

Step 2 :The function \(h(t)\) is a quadratic function, so we can solve this inequality by finding the roots of the equation \(h(t) = 1000\) and then determining which intervals of \(t\) satisfy the inequality.

Step 3 :The roots of the equation \(h(t) = 1000\) are approximately 1.05 and 48.95. This means that the projectile is at a height of 1000 feet at these two times.

Step 4 :Since the function \(h(t)\) is a downward-opening parabola (because the coefficient of \(t^2\) is negative), the projectile will be more than 1000 feet above the ground between these two times.

Step 5 :Final Answer: The projectile will be more than 1000 feet above the ground during the time interval \(\boxed{1.05 < t < 48.95}\).

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