Decide whether the normal sampling distribution can be used. If it can be used, test the claim about the population proportion p at the given level of significance $\alpha$ using the given sample statistics. Claim: $p<0.11 ; \alpha=0.05$; Sample statistics: $\hat{p}=0.08, n=25$

Step 1 ：Given that the claim is \(p<0.11\), the level of significance is \(\alpha=0.05\), and the sample statistics are \(\hat{p}=0.08\) and \(n=25\).

Step 2 ：We need to check if the normal sampling distribution can be used. The conditions for using the normal sampling distribution for a proportion are \(np \geq 5\) and \(n(1-p) \geq 5\). Here, \(n\) is the sample size and \(p\) is the population proportion.

Step 3 ：Let's calculate \(np\) and \(n(1-p)\).

Step 4 ：Given \(n = 25\) and \(p = 0.11\), we find that \(np = 2.75\) and \(n(1-p) = 22.25\).

Step 5 ：The condition \(np \geq 5\) is not satisfied as \(np = 2.75\) which is less than 5.

Step 6 ：\(\boxed{\text{The normal sampling distribution cannot be used. Therefore, we cannot test the claim about the population proportion p at the given level of significance } \alpha \text{ using the given sample statistics.}}\)