Problem

Let $A=\left[\begin{array}{rr}2 & 8 \\ -9 & 5\end{array}\right]$ and $B=\left[\begin{array}{ll}3 & 3 \\ 5 & 8\end{array}\right]$ Find $4 A+2 B$. \[ 4 A+2 B=\square \]

Solution

Step 1 :Let $A=\left[\begin{array}{rr}2 & 8 \ -9 & 5\end{array}\right]$ and $B=\left[\begin{array}{ll}3 & 3 \ 5 & 8\end{array}\right]$

Step 2 :Find $4 A+2 B$.

Step 3 :First, multiply each matrix by their respective scalars.

Step 4 :$4A = \left[\begin{array}{rr}8 & 32 \ -36 & 20\end{array}\right]$ and $2B = \left[\begin{array}{ll}6 & 6 \ 10 & 16\end{array}\right]$

Step 5 :Then, add the two resulting matrices together.

Step 6 :$4A + 2B = \left[\begin{array}{rr}14 & 38 \ -26 & 36\end{array}\right]$

Step 7 :Final Answer: The result of the operation $4A + 2B$ is $\boxed{\left[\begin{array}{rr}14 & 38 \ -26 & 36\end{array}\right]}$

From Solvely APP
Source: https://solvelyapp.com/problems/f5Vv2VDiEa/

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