Let $A=\left[\begin{array}{rr}2 & 8 \\ -9 & 5\end{array}\right]$ and $B=\left[\begin{array}{ll}3 & 3 \\ 5 & 8\end{array}\right]$ Find $4 A+2 B$. \[ 4 A+2 B=\square \]

Step 1 ：Let $A=\left[\begin{array}{rr}2 & 8 \ -9 & 5\end{array}\right]$ and $B=\left[\begin{array}{ll}3 & 3 \ 5 & 8\end{array}\right]$

Step 2 ：Find $4 A+2 B$.

Step 3 ：First, multiply each matrix by their respective scalars.

Step 4 ：$4A = \left[\begin{array}{rr}8 & 32 \ -36 & 20\end{array}\right]$ and $2B = \left[\begin{array}{ll}6 & 6 \ 10 & 16\end{array}\right]$

Step 5 ：Then, add the two resulting matrices together.

Step 6 ：$4A + 2B = \left[\begin{array}{rr}14 & 38 \ -26 & 36\end{array}\right]$

Step 7 ：Final Answer: The result of the operation $4A + 2B$ is $\boxed{\left[\begin{array}{rr}14 & 38 \ -26 & 36\end{array}\right]}$