Step 1 :The problem is asking for the time it will take for a population to grow to 150% of its current size, given a continuous growth rate of 2% per year. This is a problem of exponential growth, and we can use the formula for continuous compound interest to solve it.
Step 2 :The formula for continuous compound interest is: \(A = P \cdot e^{rt}\) where: \(A\) is the final amount (in this case, 150% of the initial population), \(P\) is the initial amount (in this case, the initial population), \(r\) is the rate of growth (in this case, 2% per year, or 0.02 when expressed as a decimal), \(t\) is the time (in years), and \(e\) is the base of the natural logarithm (approximately 2.71828).
Step 3 :We can rearrange this formula to solve for \(t\): \(t = \frac{ln(A/P)}{r}\)
Step 4 :Given that \(P = 1\), \(A = 1.5\), and \(r = 0.02\), we can plug in these values and solve for \(t\).
Step 5 :Doing so, we find that \(t = 21\).
Step 6 :Final Answer: The population of kangaroos will reach 150% of its current size in \(\boxed{21}\) years.