Find the vertex of: $f(x)=2(x-5)^{2}+5$ The vertex is

Step 1 ：Given the function \(f(x)=2(x-5)^{2}+5\).

Step 2 ：The vertex of a parabola given in the form \(f(x)=a(x-h)^{2}+k\) is simply the point \((h, k)\).

Step 3 ：In this case, the vertex is \((5, 5)\).

Step 4 ：Final Answer: The vertex of the function \(f(x)=2(x-5)^{2}+5\) is \(\boxed{(5, 5)}\).