Question 6 (1 point) \[ \int \sin (2 \pi) d x= \] a) $-\cos (2 \pi)+C$ b) $\sin (2 \pi) x+C$ c) $-\cos (2 \pi) x+C$ d) $x+C$

Step 1 ：The integral of a constant (which is what sin(2π) is, as sin(2π) = 0) with respect to x is just the constant times x.

Step 2 ：Therefore, the integral of sin(2π) dx is 0*x + C, which simplifies to just C.

Step 3 ：However, this option is not available in the choices given.

Step 4 ：The closest option to the correct answer is d) x + C, but this is not exactly correct.

Step 5 ：None of the given options are correct. The correct answer should be \(\boxed{C}\).