Problem

The exponential function given by $H(t)=80,031.11(1.0485)^{t}$, where $t$ is the number of years after 1996 , can be used to project the number of centenarians in a certain country. Use this function to project the centenarian population in this country in 1999 and in 2025. The centenarian population in 1999 is approximately $\square$. (Round to the nearest whole number)

Solution

Step 1 :Given the exponential function \(H(t)=80,031.11(1.0485)^{t}\), where \(t\) is the number of years after 1996, we can use this function to project the number of centenarians in a certain country.

Step 2 :We are asked to find the centenarian population in this country in 1999 and in 2025.

Step 3 :First, let's calculate the population for the year 1999. We subtract 1996 from 1999 to get \(t = 3\).

Step 4 :Substitute \(t = 3\) into the function to get the population for the year 1999: \(H(3) = 80,031.11(1.0485)^{3}\).

Step 5 :Calculate the value to get the approximate population for the year 1999, rounding to the nearest whole number, we get \(92,250\).

Step 6 :\(\boxed{92250}\) is the projected centenarian population in 1999.

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Source: https://solvelyapp.com/problems/eekO06giu1/

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