Consider the value of $t$ such that the area to the left of $-|t|$ plus the area to the right of $|t|$ equals 0.02 . Step 1 of 2 : Select the graph which best represents the given description of $t$.

Step 1 ：The problem describes a situation where we have a function \(f(x) = |x|\), and we're looking for a value of 't' such that the area to the left of \(-|t|\) and the area to the right of \(|t|\) equals 0.02.

Step 2 ：This means we're looking for two areas under the curve of the function that add up to 0.02. Since the function is symmetric around the y-axis, these two areas are equal. Therefore, each area is 0.01.

Step 3 ：The area under the curve of the function \(f(x) = |x|\) from 0 to t is given by the integral from 0 to t of \(|x|\) dx, which equals \(0.5*t^2\). Setting this equal to 0.01 gives us the equation \(0.5*t^2 = 0.01\).

Step 4 ：Solving this equation for t gives us \(t = \sqrt{0.02}\) = 0.1414213562373095.

Step 5 ：So, the value of t such that the area to the left of \(-|t|\) plus the area to the right of \(|t|\) equals 0.02 is approximately \(\boxed{\pm 0.1414213562373095}\).