Step 1 :Given that line segment HI is congruent to line segment JG (\(\overline{H I} \cong \overline{J G}\))
Step 2 :Given that line segment HI is parallel to line segment GJ (\(\overline{H I} \parallel \overline{G J}\))
Step 3 :Since HI is parallel to GJ, the alternate interior angles are congruent. Therefore, angle GJH is congruent to angle HJI (\(\angle G J H \cong \angle H J I\))
Step 4 :Line segment HJ is common to both triangles, so it is congruent to itself (\(\overline{H J} \cong \overline{H J}\))
Step 5 :With these three pairs of congruent parts, we can conclude that the two triangles are congruent by the ASA (Angle-Side-Angle) postulate (\(\triangle G J H \cong \Delta I H J\))
Step 6 :\(\boxed{\triangle G J H \cong \Delta I H J}\)