In a normal distribution, the mean (\(\mu\)) is 12 and the standard deviation (\(\sigma\)) is 2. Find the z-score for x = 15.

Step 1 ：Step 1: Recall the formula for the z-score, which is \(z = \frac{x - \mu}{\sigma}\), where x is the value from the data, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.

Step 2 ：Step 2: Substitute the given values into the formula. Thus, we have \(z = \frac{15 - 12}{2}\)

Step 3 ：Step 3: Simplify the expression to find the z-score. This gives \(z = \frac{3}{2} = 1.5\)