Find the derivative of the following function. \[ y=2 \cdot 3^{x} \] $y^{\prime}=$

Step 1 ：Use the rule for the derivative of an exponential function, which is \(d/dx(a^{x}) = a^{x} \cdot ln(a)\).

Step 2 ：Apply this rule to our function to get: \(y^{\prime} = 2 \cdot 3^{x} \cdot ln(3)\).

Step 3 ：\(\boxed{y^{\prime} = 2 \cdot 3^{x} \cdot ln(3)}\)