Problem

Consider the following frequency table representing the distribution of hours students watch tv in a week. \begin{tabular}{|c|c|} \hline \multicolumn{2}{|c|}{\begin{tabular}{c} Hours Students \\ Watch TV in a Week \end{tabular}} \\ \hline Class & Frequency \\ \hline $20-25$ & 10 \\ \hline $26-31$ & 12 \\ \hline $32-37$ & 11 \\ \hline $38-43$ & 14 \\ \hline $44-49$ & 10 \\ \hline \end{tabular} Step 1 of 2: Determine the relative frequency for the second class as a simplified fraction.

Solution

Step 1 :Consider the following frequency table representing the distribution of hours students watch tv in a week. \begin{tabular}{|c|c|} \hline \multicolumn{2}{|c|}{\begin{tabular}{c} Hours Students Watch TV in a Week \end{tabular}} \\ \hline Class & Frequency \\ \hline $20-25$ & 10 \\ \hline $26-31$ & 12 \\ \hline $32-37$ & 11 \\ \hline $38-43$ & 14 \\ \hline $44-49$ & 10 \\ \hline \end{tabular}

Step 2 :Determine the relative frequency for the second class as a simplified fraction. The relative frequency of a class is calculated by dividing the frequency of that class by the total frequency. In this case, the frequency of the second class is 12. The total frequency is the sum of all the frequencies, which is 10 + 12 + 11 + 14 + 10 = 57. So, the relative frequency of the second class is 12/57. This fraction can be simplified if possible.

Step 3 :The relative frequency for the second class as a simplified fraction is \(\frac{12}{57}\).

Step 4 :The simplified form of \(\frac{12}{57}\) is \(\frac{4}{19}\).

Step 5 :Final Answer: The relative frequency for the second class as a simplified fraction is \(\boxed{\frac{4}{19}}\).

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Source: https://solvelyapp.com/problems/dcaDIFsJ1R/

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