Problem

Follow the steps for graphing a rational function to graph the function $R(x)=\frac{x+4}{x(x+13)}$. Use the real zeros of the numerator and denominator of $R$ to divide the $x$-axis into intervals. Determine where the graph of $R$ is choosing a number in each interval and evaluating $\mathrm{R}$ there. Select the correct choice below and fill in the answer box(es) to com A. The graph of $R$ is above the $x$-axis on the interval(s) $\square$ and below the $x$-axis on the interval(s) $\square$. (Type your answers in interval notation. Use a comma to separate answers as needed.) B. The graph of $R$ is below the $x$-axis on the interval( $\Delta$ ) $\square$. (Type your answer in interval notation. Use a comma to separate answers as needed.) C. The graph of $R$ is above the $x$-axis on the interval(s) $\square$ (Type your answer in interval notation. Use a comma to separate answers as needed.)

Solution

Step 1 :Find the real zeros of the numerator and denominator of the function \(R(x)=\frac{x+4}{x(x+13)}\). The zeros of the numerator can be found by setting the numerator equal to zero and solving for \(x\). The zeros of the denominator can be found by setting the denominator equal to zero and solving for \(x\). These zeros will divide the \(x\)-axis into intervals.

Step 2 :The zeros of the numerator are \(x = -4\) and the zeros of the denominator are \(x = -13, 0\). These zeros divide the \(x\)-axis into the intervals \((-\infty, -13)\), \((-13, 0)\), \((0, -4)\), and \((-4, \infty)\).

Step 3 :Determine where the graph of \(R\) is above or below the \(x\)-axis. This can be done by choosing a number in each interval and evaluating \(R\) there. If the value of \(R\) is positive, the graph is above the \(x\)-axis on that interval. If the value of \(R\) is negative, the graph is below the \(x\)-axis on that interval.

Step 4 :The values of \(R\) in the intervals \((-\infty, -13)\), \((-13, 0)\), \((0, -4)\), and \((-4, \infty)\) are NaN, 0.059, -0.091, and NaN respectively. The NaN values indicate that \(R\) is undefined at the zeros of the denominator. The positive value indicates that the graph of \(R\) is above the \(x\)-axis on the interval \((-13, 0)\) and the negative value indicates that the graph of \(R\) is below the \(x\)-axis on the interval \((0, -4)\).

Step 5 :Final Answer: The graph of \(R\) is above the \(x\)-axis on the interval \((-13, 0)\) and below the \(x\)-axis on the interval \((0, -4)\). In interval notation, this is written as \(\boxed{(-13, 0)}\) and \(\boxed{(0, -4)}\).

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Source: https://solvelyapp.com/problems/dcAcIjwcbZ/

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