Write $y-\frac{2}{3}=\frac{4}{3}(x+2)$ in standard form. An equation is

Step 1 ：Given equation is: \(y - \frac{2}{3} = \frac{4}{3}(x + 2)\)

Step 2 ：Distribute \(\frac{4}{3}\) to the terms inside the parentheses: \(y - \frac{2}{3} = \frac{4}{3}x + \frac{8}{3}\)

Step 3 ：Multiply every term by 3 to eliminate the fractions: \(3y - 2 = 4x + 8\)

Step 4 ：Rearrange the equation to standard form: \(4x - 3y = -6\)

Step 5 ：\(\boxed{4x - 3y = -6}\) is the equation in standard form