Animals in an experiment are to be kept under a strict diet. Each animal should receive 30 g of protein and 8 g of fat. The laboratory technician is able to purchase two food mixes: Mix A has $10 \%$ protein and $6 \%$ fat, mix B has $40 \%$ protein and $4 \%$ fat. How many grams of each mix should be used to obtain the right diet for one animal? One arimar's diet should consist of 100 grams of Mix A. One animars diet choutd coneter of $\square$ grems of Mix $\mathbf{B}$

Step 1 ：Let's denote the amount of mix A as x and the amount of mix B as y. Then, the total amount of protein is given by \(0.1x + 0.4y = 30\), and the total amount of fat is given by \(0.06x + 0.04y = 8\).

Step 2 ：We can solve this system of equations to find the values of x and y.

Step 3 ：The solution to the system of equations is x = 100 and y = 50.

Step 4 ：This means that to obtain the right diet for one animal, 100 grams of mix A and 50 grams of mix B should be used.

Step 5 ：Final Answer: One animal's diet should consist of \(\boxed{50}\) grams of Mix B.