Solve for the value of \( x \) in the following equation: \(2^{x+3}=32\).

Step 1 ：We know that 32 can be written as \(2^{5}\), so we can rewrite the equation as \(2^{x+3}=2^{5}\).

Step 2 ：Since the bases are the same, we can equate the exponents. So, \(x+3=5\).

Step 3 ：Subtract 3 from both sides of the equation to solve for \(x\), which results in \(x=5-3\).