Part 2 of 3 Points: 0 of 1 Graph the following function using the techniques of shifting, compressing, stretching, and/or reflecting. Start with the graph of the basic function shown to the right. Find the domain and range of the function. \[ h(x)=\sqrt{-x}-2 \] Choose the correct graph below. A. B. C. D. The domain of $h(x)=\sqrt{-x}-2$ is $\square$ (Type your answer in interval notation.)

Step 1 ：The function \(h(x) = \sqrt{-x} - 2\) is a transformation of the basic function \(f(x) = \sqrt{x}\). The negative sign before x reflects the graph of \(f(x)\) over the y-axis, and the -2 shifts the graph down by 2 units.

Step 2 ：The domain of the function \(h(x)\) is the set of all real numbers x for which -x is greater than or equal to 0, because we cannot take the square root of a negative number. This means that x must be less than or equal to 0.

Step 3 ：In interval notation, this is written as \((-∞, 0]\).

Step 4 ：The graph of the function \(h(x) = \sqrt{-x} - 2\) confirms this. It is a reflection of the graph of \(f(x) = \sqrt{x}\) over the y-axis, and it is shifted down by 2 units. The domain of the function is indeed all real numbers less than or equal to 0.

Step 5 ：Final Answer: The domain of \(h(x)=\sqrt{-x}-2\) is \(\boxed{(-\infty, 0]}\).