Given the function $f(x)=x^{2}-x+6$, find each of the following. $f(8), f(-5), f(0)$ \[ \begin{array}{l} f(8)=\square \\ f(-5)=\square \\ f(0)=\square \end{array} \] (Simplify your answers. Type an integer or a fraction.)

Step 1 ：The function given is \(f(x)=x^{2}-x+6\).

Step 2 ：To find \(f(8)\), substitute \(x=8\) into the function to get \(f(8)=8^{2}-8+6=62\).

Step 3 ：To find \(f(-5)\), substitute \(x=-5\) into the function to get \(f(-5)=(-5)^{2}-(-5)+6=36\).

Step 4 ：To find \(f(0)\), substitute \(x=0\) into the function to get \(f(0)=0^{2}-0+6=6\).

Step 5 ：So, the final answers are \(f(8)=\boxed{62}\), \(f(-5)=\boxed{36}\), and \(f(0)=\boxed{6}\).