Question Gianna is going to throw a ball from the top floor of her middle school. When she throws the ball from 48 feet above the ground, the function $h(t)=-16 t^{2}+32 t+48$ models the height, $h$, of the ball above the ground as a function of time, $t$. Find the times the ball will be 48 feet above the ground.

Step 1 ：The problem is asking for the times when the ball will be 48 feet above the ground. This means we need to solve the equation \(h(t) = 48\) for \(t\). The equation is \(-16 t^{2}+32 t+48 = 48\).

Step 2 ：We can simplify this equation by subtracting 48 from both sides, which gives us \(-16 t^{2}+32 t = 0\).

Step 3 ：This is a quadratic equation, and we can solve it by factoring, completing the square, or using the quadratic formula. In this case, factoring seems to be the easiest method.

Step 4 ：We can factor out a \(-16t\) from both terms on the left side of the equation, which gives us \(-16t(t - 2) = 0\).

Step 5 ：Setting each factor equal to zero gives us the solutions \(t = 0\) and \(t = 2\). These are the times when the ball will be 48 feet above the ground.

Step 6 ：Final Answer: The times when the ball will be 48 feet above the ground are \(\boxed{0}\) and \(\boxed{2}\) seconds.